The linear systems in Problems 110 are in echelon form. Solve each by back substitution. x 1

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The linear systems in Problems 1–10 are in echelon form. Solve each by back substitution.

x₁ - 2x₂ + 5x₃ - 3x₄ = 7

x₂ - 3x₃ + 2x₄ = 3

X₄ = -4

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Differential Equations And Linear Algebra

ISBN: 9780134497181

4th Edition

Authors: C. Edwards, David Penney, David Calvis

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Question Posted: Jul 05, 2023 07:31 AM

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The linear systems in Problems 110 are in echelon form. Solve each by back substitution. x 1 + 2x 2 + 4x 3 - 5x 4 = 17 x 2 - 2x 3 + 7x 4 = 7
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The linear systems in Problems 110 are in echelon form. Solve each by back substitution. x 1

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Differential Equations And Linear Algebra

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