Use the method of Examples 7 and 8 to find the Jordan normal form J of each coefficient matrix A given in Problems 23 through 32 (respectively).

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Example 7 In Example 3 we saw that the matrix ^=[03] A 7 = has the single eigenvalue > {V₁, V2), where V₁ = [-3 If we define 4 and the associated length 2 chain of generalized eigenvectors 3] and v₂ = [1 0], based on the eigenvector v₁ = Av₂. [3] Q=[V₁ V2] = then we find that the Jordan normal form of A is 4 J=Q-¹AQ = [1 4]. Here J = J₁ is a single 2 × 2 Jordan block corresponding to the single eigenvalue λ = 4 of A.