For the linkage in the posture shown, a constant external torque T12 = 180k inlb is acting

For the linkage in the posture shown, a constant external torque T12 = 180kˆ in·lb is acting on link 2 about shaft O2, and a horizontal external force P is acting on link 5 to hold the linkage in static equilibrium. Assume that gravity is acting into the plane and effects of friction in the linkage can be neglected.

(a) Draw free-body diagrams for links 2, 3, 4, 5, and 6.

(b) Determine the magnitudes, directions, and locations of the internal reaction forces.

(c) Determine the magnitude and direction of the external force P.

Figure P11.36 RO2O = 7.0ˆi+ 5.0ˆj in, RAO2 =

5.0 in, RBA = 2.75 in, RCD = 6.0 in, and RBD = 2.818 in.

Blocks 5 and 6 are each 2 in by 1 in with the pins centrally located.