Link BC = 1.2 m and 25 mm square cross section is fixed in the vertical wall
Question:
Link BC = 1.2 m and 25 mm square cross section is fixed in the vertical wall at C and pinned at B to a circular steel cable, AB, with diameter d = 20 mm. Distance AC = 0.7 m. The mass, m, of a container, suspended from pin B, produces a gravitational load at B, which results in the moment at point C in the wall MC = 8 000N · m ccw. The yield strength and modulus of elasticity of the steel cable AB and the steel link BC are Sy =
370 MPa and E = 207 GPa, respectively. Given that m = 2 000 kg, determine:
(a) the tension in the cable AB and the factor of safety guarding against tensile failure;
(b) the compressive load acting in link BC;
(c) the factor of safety guarding against buckling of link BC. (Use the theoretic value of the end-condition constant assuming that the link has fixed-pinned ends.) If MC =
10 000 N · m ccw, then determine the maximum mass of a container that can be suspended from pin B before buckling of link BC begins (that is, the factor of safety guarding against buckling failure is N = 1).
Figure P11.45 Structure supporting a load.
Step by Step Answer:
Theory Of Machines And Mechanisms
ISBN: 9780190264482,9780190264536
5th Edition
Authors: John J. Uicker Jr, Gordon R. Pennock, Joseph E. Shigley