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The 0.5-m-radius semi-circular gate shown in the figure is hinged

The 0.5-m-radius semi-circular gate shown in the figure is hinged through the top edge AB. Find the

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The 0.5-m-radius semi-circular gate shown in the figure is hinged through the top edge AB. Find the required force to be applied at the center of gravity to keep the gate closed.

= 80 kPa (abs) alr %3D 4.74 m Oil SG = 0.91 в CG Glycerin SG = 1.26 u.

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= 80 kPa (abs) alr %3D 4.74 m Oil SG = 0.91 в CG Glycerin SG = 1.26 u.

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Fundamentals of Thermal-Fluid Sciences

ISBN: 978-0078027680

5th edition

Authors: Yunus A. Cengel, Robert H. Turner, John M. Cimbala

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Question Posted: Oct 05, 2018 01:53 PM

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The 0.5-m-radius semi-circular gate shown in the figure is hinged through the top edge AB. Find the

Question:

= 80 kPa (abs) alr %3D 4.74 m Oil SG = 0.91 в CG Glycerin SG = 1.26 u.

Step by Step Answer:

A semicircular gate is hinged The required force at the center of gravi...View the full answer

Fundamentals of Thermal-Fluid Sciences

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