How many milliliters of 0.250 M KMnO 4 are needed to react with 3.55 g of iron(II)
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How many milliliters of 0.250 M KMnO4 are needed to react with 3.55 g of iron(II) sulfate, FeSO4? The reaction is as follows:
Transcribed Image Text:
10FESO,(aq) + 2KMNO,(aq) + 8H,SO,(aq) → 5Fe,(SO4);(aq) + 2MNSO,(aq) + K,SO,(aq) + 8H,O(1)
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The reaction is 10FeSO4 2KMnO4 8HSO...View the full answer
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