A spherical particle of radius \(r_{1}=5 \mathrm{~mm}\) is suspended by a thin wire within a cylindrical tube of inner radius \(r_{2}=15 \mathrm{~mm}\) and length \(L=0.5 \mathrm{~m}\). Determine the view factors \(F_{11}, F_{12}, F_{13}\), and \(F_{14}\) for \(S=5\) and \(250 \mathrm{~mm}\). The view factor between the sphere and the bottom end of the tube (a disk of radius \(r_{3}\) ) is \(F_{13}=0.5\left[1-\left(1+R_{3}^{2}\right)^{-1 / 2}\right]\) where \(R_{3}=r_{3} / S\).

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L + A4 A2 D2 S H -A3