By considering the reactions 8E(g) 4E 2 (g) and 8E(g) E 8 (g) for E
Question:
By considering the reactions 8E(g) → 4E2(g) and 8E(g) → E8(g) for E = O and E = S, show that the formation of diatomic molecules is favoured for oxygen, whereas ring formation is favoured for sulfur. [Data: see Table 16.2.]
Table 16.2.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
To determine whether the formation of diatomic molecules or ring formation is favored for oxygen O and sulfur S we need to compare the enthalpy changes H for the two reactions 8Eg 4E2g and 8Eg E8g for E O and E S Lets consider the data from Table 162 for oxygen O and sulfur S For oxygen O Enthalpy change ...View the full answer
Answered By
Surendar Kumaradevan
I have worked with both teachers and students to offer specialized help with everything from grammar and vocabulary to challenging problem-solving in a range of academic disciplines. For each student's specific needs, I can offer explanations, examples, and practice tasks that will help them better understand complex ideas and develop their skills.
I employ a range of techniques and resources in my engaged, interesting tutoring sessions to keep students motivated and on task. I have the tools necessary to offer students the support and direction they require in order to achieve, whether they need assistance with their homework, test preparation, or simply want to hone their skills in a particular subject area.
0 Reviews
10+ Question Solved
Related Book For 
Question Posted:
