5 kg of steam at (14 mathrm{bar}, 280^{circ} mathrm{C}) expands to (1.4 mathrm{bar}) according to the law

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5 kg of steam at \(14 \mathrm{bar}, 280^{\circ} \mathrm{C}\) expands to \(1.4 \mathrm{bar}\) according to the law \(p v^{1.25}=\) constant. Calculate \((a)\) the final temperature, \((b)\) the work done, \((c)\) heat transferred, and \((d)\) change in entropy.

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