LMTD for a heat exchanger is given by: (a) (frac{Delta t_{2}-Delta t_{1}}{log _{e} frac{Delta t_{2}}{Delta t_{1}}}) (b)
Question:
LMTD for a heat exchanger is given by:
(a) \(\frac{\Delta t_{2}-\Delta t_{1}}{\log _{e} \frac{\Delta t_{2}}{\Delta t_{1}}}\)
(b) \(\frac{\Delta t_{2}-\Delta t_{1}}{\log _{e} \frac{\Delta t_{1}}{\Delta t_{2}}}\)
(c) Both
(d) None of these
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: