Calculate the equilibrium constant at (750 mathrm{~K}) and 1 bar for the following reaction: [ mathrm{C}_{2} mathrm{H}_{5}
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Calculate the equilibrium constant at \(750 \mathrm{~K}\) and 1 bar for the following reaction:
\[ \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CH}_{3} \mathrm{CHO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \]
Assume that the heat of reaction remains constant in the temperature range involved, given that the equilibrium constant \(K\) at \(298 \mathrm{~K}\) and 1 bar is \(1.1582 \times 10^{5}\). Use data table for standard heat of reaction.
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