Calculate the theoretical temperature of combustion of ethane with \(25 \%\) excess air. The average specific heats in \(\mathrm{kJ} / \mathrm{kg}-\mathrm{K}\) may be taken as follows:

\[ \begin{aligned} \mathrm{CO}_{2} & =54.56 \mathrm{~kJ} / \mathrm{kmol}-\mathrm{K} \\ \mathrm{O}_{2} & =35.20 \mathrm{~kJ} / \mathrm{kmol}-\mathrm{K} \\ \text { Steam } & =43.38 \mathrm{~kJ} / \mathrm{kmol}-\mathrm{K} \\ \mathrm{N}_{2} & =33.32 \mathrm{~kJ} / \mathrm{kmol}-\mathrm{K} \end{aligned} \]

The combustion reaction for ethane is

\[ 2 \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{~g})+7 \mathrm{O}_{2}(\mathrm{~g})=4 \mathrm{CO}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \quad \Delta H_{273}=-1560000 \mathrm{~kJ} / \mathrm{kmol} \]