Using Maxwell's relation, prove that [ left(frac{partial S}{partial V} ight)_{T}=left(frac{partial P}{partial T} ight)_{V}=frac{beta}{alpha} ]
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Using Maxwell's relation, prove that
\[ \left(\frac{\partial S}{\partial V}\right)_{T}=\left(\frac{\partial P}{\partial T}\right)_{V}=\frac{\beta}{\alpha} \]
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