A pair of random variables has the circular normal distribution if their joint density is given by

Question:

A pair of random variables has the circular normal distribution if their joint density is given by

\[\begin{aligned}& f\left(x_{1}, x_{2}\right) \\& \quad=\frac{1}{2 \pi \sigma^{2}} e^{-\left[\left(x_{1}-\mu_{1}\right)^{2}+\left(x_{2}-\mu_{2}\right)^{2}\right] / 2 \sigma^{2}} \\& \text { for }-\infty

(a) If \(\mu_{1}=2\) and \(\mu_{2}=-2\), and \(\sigma=10\), use Table 3 to find the probability that \(-8

(b) If \(\mu_{1}=\mu_{2}=0\) and \(\sigma=3\), find the probability that \(\left(X_{1}, X_{2}\right)\) is contained in the region between the two circles \(x_{1}^{2}+x_{2}^{2}=9\) and \(x_{1}^{2}+x_{2}^{2}=36\).

Data From Table 3

image text in transcribed

image text in transcribed

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Probability And Statistics For Engineers

ISBN: 9780134435688

9th Global Edition

Authors: Richard Johnson, Irwin Miller, John Freund

Question Posted: