For any nonnegative integer, n, show that (3n)! is divisible by 2n3n.

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Introduction To Probability Volume 2

ISBN: 9781118123331

1st Edition

Authors: Narayanaswamy Balakrishnan, Markos V. Koutras, Konstadinos G. Politis

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Question Posted: Sep 19, 2024 02:31 PM

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For any nonnegative integer, n, show that (3n)! is divisible by 2n3n.
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For any nonnegative integer, n, show that (3n)! is divisible by 2n3n.

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Introduction To Probability Volume 2

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