Show that if (mu_{i}=mu+alpha_{i}) and (mu) is the mean of the (mu_{i}), it follows that [sum_{i=1}^{k} n_{i}

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Show that if \(\mu_{i}=\mu+\alpha_{i}\) and \(\mu\) is the mean of the \(\mu_{i}\), it follows that

\[\sum_{i=1}^{k} n_{i} \alpha_{i}=0\]

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Probability And Statistics For Engineers

ISBN: 9780134435688

9th Global Edition

Authors: Richard Johnson, Irwin Miller, John Freund

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