Verify that

(a) the exponential density \(0.3 e^{-0.3 x}, x>0\) corresponds to the distribution function \(F(x)=\) \(1-e^{-0.3 x}, x>0\)

(b) the solution of \(u=F(x)\) is given by \(x=\) \([-\ln (1-u)] / 0.3\).