Question: Find the best bound on for the delta function potential V(x) = -(x), using a triangular trial function (Equation 8.10, only centered at the origin).

Find the best bound on for the delta function potential V(x) = -δ(x), using a triangular trial function (Equation 8.10, only centered at the origin). This time a is an adjustable parameter.

Ax, (x) = A (a-x), 0, 0 x a/2, a/2 x a,

Ax, (x) = A (a-x), 0, 0 x a/2, a/2 x a, otherwise, (8.10)

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