A 25.0-g sample of rock at 250 C is dropped into 100.0 g of water at 19
Question:
A 25.0-g sample of rock at 250 °C is dropped into 100.0 g of water at 19 °C. If the water temperature rises to 31 °C as the rock cools, what is the specific heat of the rock?
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Strategy Plan STEP 1: What unit is asked for in the answer? STEP 2: What given value is related to the answer? Step 2: STEP 3: What unit factor should we apply? From the definition of specific heat, 1.00 cal = 1 g x °C; the two unit factors are 1.00 cal = 1 g x °C, and its reciprocal 1 g x °C = 1.00 cal. Unit Analysis Map given value 100.0 g unit factor 1gx °C 1.00 cal Step 1: or Step 3: 1.00 cal 1gx °C unit in answer ? cal/g x °C = cal/(g x °C) 100.0 g water 1gx °C 1.00 cal or 1.00 cal 1gx °C
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We can cancel grams and degrees Celsius by applying the unit factor 1 0 0 cal1 g x C and multiplyi...View the full answer
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Related Book For
Introductory Chemistry Concepts And Critical Thinking
ISBN: 9780321804907
7th Edition
Authors: Charles Corwin
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