What volume of 0.128 M calcium hydroxide is required to neutralize 1.466 g of potassium hydrogen phthalate,
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What volume of 0.128 M calcium hydroxide is required to neutralize 1.466 g of potassium hydrogen phthalate, KHC8H4O4 (204.23 g/mol)?
2 KHC8H4O4(aq) + Ca(OH)2(aq) → CaK2(C8H4O4)2(aq) + 2 H2O(l)
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Related Book For 
Introductory Chemistry Concepts And Critical Thinking
ISBN: 9780321804907
7th Edition
Authors: Charles Corwin
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