Equations (10.30) and (10.32) give bIV as (a) Follow equations (2.31) through (2.33) to transform the numerator
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Equations (10.30) and (10.32) give bIV as
(a) Follow equations (2.31) through (2.33) to transform the numerator into Σ − − i= n i i z z y y 1( )( ) and the denominator into Σ − − i= n i i z z x x 1( )( ).
(b) What else must be done in order to transform the above formula for bIV into
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