Find the projection of v onto u. Figure 1.39 suggests two ways in which vectors may be
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Figure 1.39 suggests two ways in which vectors may be used to compute the area of a triangle. The area A of
the triangle in part (a) is given by 1 / 2 ¥u¥¥v - proju(v)¥, and part (b) suggests the trigonometric from of the area of a triangle: A = 1 / 2¥u¥¥v¥sinθ (We can use the identity sinθ = 1 - cos2θ to find sin θ.)
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