A flat belt drive is required to transmit (20 mathrm{~kW}) at (300 mathrm{rpm}) of (2 mathrm{~m}) diameter
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A flat belt drive is required to transmit \(20 \mathrm{~kW}\) at \(300 \mathrm{rpm}\) of \(2 \mathrm{~m}\) diameter pulley. The angle of contact is \(170^{\circ}\) and coefficient of friction between belt and pulley is 0.30 . The permissible stress for belt material is \(3 \mathrm{MPa}\). Thickness of belt is \(8 \mathrm{~mm}\) and density of its material is \(0.95 \mathrm{~kg} / \mathrm{m}^{3}\). Find the width of belt required taking centrifugal tension into account.
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