Question: In a compound gear train having (mathrm{m}) gears, the ratio of speed of last gear to first gear is (a) (frac{text { product of teeth

In a compound gear train having \(\mathrm{m}\) gears, the ratio of speed of last gear to first gear is

(a) \(\frac{\text { product of teeth of driving gears }(\mathrm{X})}{\text { product of teeth of driven gears }(Y)}\)

(b) \(y / x\)

(c) \(X-Y\)

(d) \(\left(\frac{x}{y}\right)^{2}\)

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