The BF 3 molecule is planar with bond angles of 120 . (a) List the symmetry
Question:
The BF3 molecule is planar with bond angles of 120◦.
(a) List the symmetry operators that belong to this molecule. We place the molecule in the x–y plane with the boron atom at the origin and one of the fluorine atoms on the x axis. Call the fluorine atoms a, b, and c starting at the x axis and proceeding counterclockwise around the x–y plane. The symmetry elements are: a threefold rotation axis, three vertical mirror planes containing a fluorine atom, the horizontal mirror plane, and three twofold rotation axes containing a fluorine atom.
(b) Find the three-dimensional matrices corresponding to the operators:
(i) Ĉ3(z).
(ii) σ̂a.
(iii) Ĉ2a.
(c) Find the following operator products:
(i) Ĉ3(z) σ̂a.
(ii) σ̂a σ̂h.
(iii) Ĉ3(z) Ĉ2a.
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