A (pi^{-})meson with mass (m_{pi}=140.0 mathrm{MeV} / c^{2}) is produced in a ((p, p)) collision in an

Question:

A \(\pi^{-}\)meson with mass \(m_{\pi}=140.0 \mathrm{MeV} / c^{2}\) is produced in a \((p, p)\) collision in an accelerator. The pion subsequently decays into a muon and a muon-type antineutrino, in the reaction \(\pi^{-} ightarrow \mu^{-}+\bar{u}_{\mu}\). The antineutrino has a non-zero but very small mass, so in this calculation you can ignore it. The muon has a mass-energy of \(105.7 \mathrm{MeV} / \mathrm{c}^{2}\). In the rest-frame of the original pion, find

(a) The total energy and three-momentum of the muon,

(b) The total energy and three-momentum of the antineutrino.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Modern Classical Mechanics

ISBN: 9781108834971

1st Edition

Authors: T. M. Helliwell, V. V. Sahakian

Question Posted: