A (pi^{-})meson with mass (m_{pi}=140.0 mathrm{MeV} / c^{2}) is produced in a ((p, p)) collision in an
Question:
A \(\pi^{-}\)meson with mass \(m_{\pi}=140.0 \mathrm{MeV} / c^{2}\) is produced in a \((p, p)\) collision in an accelerator. The pion subsequently decays into a muon and a muon-type antineutrino, in the reaction \(\pi^{-} ightarrow \mu^{-}+\bar{u}_{\mu}\). The antineutrino has a non-zero but very small mass, so in this calculation you can ignore it. The muon has a mass-energy of \(105.7 \mathrm{MeV} / \mathrm{c}^{2}\). In the rest-frame of the original pion, find
(a) The total energy and three-momentum of the muon,
(b) The total energy and three-momentum of the antineutrino.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: