Question: CP2.7 For the simple pendulum shown in Figure CP2.7, the nonlinear equation of motion is given by (1) +15 sin (t) = 0, where L

CP2.7 For the simple pendulum shown in Figure CP2.7, the nonlinear equation of motion is given by(1) +15 sin (t) = 0, where L = 0.5 m, m

(1) +15 sin (t) = 0, where L = 0.5 m, m = 1 kg, and g = 9.8 m/s. When the nonlinear equation is linearized about the equilibrium point = 0, we obtain the linear time-invariant model, (1) +0(1) = 0. L Create an m-file to plot both the nonlinear and the linear response of the simple pendulum when the ini- tial angle of the pendulum is (0) = 30 and explain any differences. L, length 0(t) m, mass FIGURE CP2.7 Simple pendulum.

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock