Question: (a) Show by direct sustitution into the recurrence relation that x n = 3 n and x n = (2) n are two solutions. (b)

(a) Show by direct sustitution into the recurrence relation

Xn+2 Xn+1 6x=0 'n

that xn = 3n and xn = (–2)n are two solutions.

(b) Further verify that xn = A(–2)n + B3n, where A and B are constants, is also a solution.

Xn+2 Xn+1 6x=0 'n

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