According to the inverse square law, the force on a particle of mass m 1 at the

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According to the inverse square law, the force on a particle of mass m1 at the point P1 due to a particle of mass m2 at the point P2 is given by

mm where r = PP Y p. 840

Particles of mass 3m, 3m, m are fixed at the points A(1, 0, 1), B(0, 1, 2) and C(2, 1, 2) respectively. Show that the force on the particle at A due to the presence of B and C is

2yma V3 -(-1, 2, 2)

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