Question: Newtons recurrence formula for determining the root of a certain equation is Taking x 0 = 3 as your initial approximation, obtain the root correct

Newton’s recurrence formula for determining the root of a certain equation is

Xn+l x-1 n 2x - 3

Taking x₀ = 3 as your initial approximation, obtain the root correct to 4sf. By setting x_{n + 1} = x_n = α show that the fixed points of the iteration are given by the equation α² – 3α + 1 = 0.

Xn+l x-1 n 2x - 3

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