Question: The equations define u as a function of y if x and z are eliminated. Find du/dy when x = 1, y = 1, z
The equations

define u as a function of y if x and z are eliminated. Find du/dy when x = 1, y = –1, z = 2, u = –2.
x + 2y + 3z + 4u = -3 x + y+z+u =10 x + y + z + u =0
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The total derivatives of the equations are dx 2dy 3dz 4du 0 2xdx 2ydy ... View full answer
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