Use integration by parts (writing the integrand as sin sin n1 ) to show that satisfies

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Use integration by parts (writing the integrand as sin θ sinn–1θ) to show that

IS 0 J 70/2 = || = "1

satisfies the reduction formula

nl, = (n - 1)In-2

Hence prove that

and 12k+1 = 2k 2k 2k-2 2k + 1 2k - 1 2k-12k-3 2k 2k-2 2 3 1 T 22

These results are known as Wallis’s formulae. Use them to show that

(a) 7/2 (b) [ 0 sinx dx = (b) 15 cos xdx = I

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