=+17.13. 1 Let A (f) be the Riemann integral of f, which does exist for f in

Question:

=+17.13. 1 Let A

(f) be the Riemann integral of

f, which does exist for f in 1.

Using the most elementary facts about Riemann integration, show that the u determined by (17.25) is Lebesgue measure. This gives still another way of constructing Lebesgue measure.

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