=+3.20. 1 There is no Borel set A in (0, 1) such that al(I) A(ANI) sbA(I)
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=+3.20. 1 There is no Borel set A in (0, 1) such that al(I) ≤ A(ANI) sbA(I) for every open interval / in (0, 1), where 0 < a sb < 1. In fact prove:
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Related Book For 
Probability And Measure Wiley Series In Probability And Mathematical Statistics
ISBN: 9788126517718
3rd Edition
Authors: Patrick Billingsley
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