=+5.20. 1 (a) From Stirling's formula, deduce (5.48) E[log] = log n +0(1). From this, the inequality

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=+5.20. 1

(a) From Stirling's formula, deduce

(5.48)

E„[log] = log n +0(1).

From this, the inequality E,[@ ] ≤ 2/ p, and the relation log m = Ep@ (m) log p.

conclude that Epp" log p diverges and that there are infinitely many primes.

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