Question: Consider the binding reaction L + R LR, where L is a ligand and R is its receptor. When 1 X 10 -3 M

Consider the binding reaction L + R → LR, where L is a ligand and R is its receptor. When 1 X 10^-3 M L is added to a solution containing 5 X 10^-2 M R, 90 percent of the L binds to form LR. What is the K cq of this reaction? How will the Keq be affected by the addition of a protein that facilitates (catalyzes) this binding reaction? What is the dissociation equilibrium constant Kd?

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K eq LR LR Since 90 of L binds R the concentration of LR at equilibrium is 091 10 3 ... View full answer

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