8. Leveling the Terrain for a New Highway. (Stark and Nicholes, 1972) The Arkansas Highway Department is
Question:
8. Leveling the Terrain for a New Highway. (Stark and Nicholes, 1972) The Arkansas Highway Department is planning a new 10-mile highway on uneven terrain as shown by the profile in Figure 2.10.The width of the construction terrain is approximately 50 yards.To simplify the situation, the terrain profile can be replaced by a step function as shown in the figure. Using heavy machinery, earth removed from high terrain is hauled to fill low areas. There are also two burrow pits, I and II, located at the ends of the lO-mile stretch from which additional earth can be hauled, if needed. Pit I has a capacity of 20,000 cubic yards and pit II a capacity of 15,000 cubic yards. TIle costs of removing earth from pits I and II are, respectively, $1.50 and $1.90 per cubic yard.The transportation cost per cubic yard per mile is $.15 and the cost of using heavy machinery to load hauling trucks is $.20 per cubic yard. This means that a
+20
+100 o
-10
-20 FIGURE 2.10
f- J" \ I \ " , , \ , "', , \ \
J , I , , I , , I I I , I I 10 I I , I , , I I
, I I I 1 3 5 7 8 9
, , I \ /
I, / J I , I I , I I , , ,,
- , I, I \ , / I \ , I I "' ~
, I
, -- I I
f- , I I I , I I I I
\, Mile t
i.
i:
l ..
Terrain profile for Problem 8 66 Chapter 2 Modeling with linear Programming cubic yard from pit I hauled one mile will cost a total of (1.5 + .20) + 1 X .15 = $1.85 and a cubic yard hauled one mile from a hill to a fill area will cost .20 + 1 x .15 = $.35. Develop a minimum cost plan for leveling the lO-mile stretch.
Step by Step Answer: