Question: A horizontal hole 2.00 mm by 1.00 mm in an opaque screen is illuminated normally by a beam of collimated light of wavelength 500 nm.
A horizontal hole 2.00 mm by 1.00 mm in an opaque screen is illuminated normally by a beam of collimated light of wavelength 500 nm. If the incident irradiance is 30.0 W/m2, calculate the approximate irradiance at a point 5.0 m from the hole on the central axis.
Step by Step Solution
3.54 Rating (171 Votes )
There are 3 Steps involved in it
For a collimated l... View full answer
Get step-by-step solutions from verified subject matter experts
