A (0.010-mathrm{kg}) bullet traveling at (300 mathrm{~m} / mathrm{s}) hits a (2.0-mathrm{kg}) ballistic pendulum like the one
Question:
A \(0.010-\mathrm{kg}\) bullet traveling at \(300 \mathrm{~m} / \mathrm{s}\) hits a \(2.0-\mathrm{kg}\) ballistic pendulum like the one described in Problem 110. However, the block is not thick enough for this bullet, and the bullet passes through the block, exiting with onethird of its original speed. How high above its original position does the block rise?
Data from Problem 110
A ballistic pendulum is a device for measuring bullet speeds. One of the simplest versions consists of a block of wood hanging from two long cords. (Two cords are used so that the bottom face of the block remains parallel to the floor as the block swings upward.) A 9. 5-g bullet is fired into a ballistic pendulum in which the block has an inertia of \(5.0 \mathrm{~kg}\), and the block rises \(60 \mathrm{~mm}\) above its initial position.
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