A (0.70-mathrm{kg}) basketball dropped on a hardwood floor rises back up to (65 %) of its original
Question:
A \(0.70-\mathrm{kg}\) basketball dropped on a hardwood floor rises back up to \(65 \%\) of its original height.
(a) If the basketball is dropped from a height of \(1.5 \mathrm{~m}\), how much energy is dissipated in the first bounce?
(b) How much energy is dissipated in the fourth bounce?
(c) To which type of incoherent energy is the dissipated energy converted?
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Step by Step Answer:
To solve this problem we can use the principle of conservation of mechanical energy When the basketb...View the full answer
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Somshukla Chakraborty
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