Question: A force (vec{F}=F_{x} hat{imath}+F_{y} hat{jmath}) with (F_{x}=50 mathrm{~N}) and (F_{y}=12 mathrm{~N}) is exerted on a particle as the particle moves along the (x) axis from
A force \(\vec{F}=F_{x} \hat{\imath}+F_{y} \hat{\jmath}\) with \(F_{x}=50 \mathrm{~N}\) and \(F_{y}=12 \mathrm{~N}\) is exerted on a particle as the particle moves along the \(x\) axis from \(x=1.0 \mathrm{~m}\) to \(x=-5.0 \mathrm{~m}\).
(a) Determine the work done by the force on the particle.
(b) What is the angle between the force and the particle's displacement?
Step by Step Solution
3.43 Rating (150 Votes )
There are 3 Steps involved in it
To determine the work done by the force on the particle we can use the formula textWork vecF cdot ve... View full answer
Get step-by-step solutions from verified subject matter experts
