Question: A force (vec{F}=F_{x} hat{imath}+F_{y} hat{jmath}) with (F_{x}=50 mathrm{~N}) and (F_{y}=12 mathrm{~N}) is exerted on a particle as the particle moves along the (x) axis from

A force \(\vec{F}=F_{x} \hat{\imath}+F_{y} \hat{\jmath}\) with \(F_{x}=50 \mathrm{~N}\) and \(F_{y}=12 \mathrm{~N}\) is exerted on a particle as the particle moves along the \(x\) axis from \(x=1.0 \mathrm{~m}\) to \(x=-5.0 \mathrm{~m}\).

(a) Determine the work done by the force on the particle. 

(b) What is the angle between the force and the particle's displacement?

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To determine the work done by the force on the particle we can use the formula textWork vecF cdot ve... View full answer

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