An object's position as a function of time is given by (x(t)=-2.0 t^{2}+1.0 t^{3}). Calculate ((a)) the
Question:
An object's position as a function of time is given by \(x(t)=-2.0 t^{2}+1.0 t^{3}\). Calculate
\((a)\) the object's position and velocity at \(t=2 \mathrm{~s}\).
(b) The average velocity between \(t=0\) and \(t=2 \mathrm{~s}\).
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