Calculated using the value (g=9.8 mathrm{~m} / mathrm{s}^{2}), the time interval required for an object released from
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Calculated using the value \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\), the time interval required for an object released from rest at some arbitrary point \(\mathrm{A}\) above the ground to reach the ground is \(\Delta t\). If \(g\) were \(4.9 \mathrm{~m} / \mathrm{s}^{2}\), by what factor would \(\Delta t\) differ from the value calculated using \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) ?
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