Sledding down a hill, you are traveling at (10 mathrm{~m} / mathrm{s}) when you reach the bottom.
Question:
Sledding down a hill, you are traveling at \(10 \mathrm{~m} / \mathrm{s}\) when you reach the bottom. You (inertia \(70 \mathrm{~kg}\) ) then move across horizontal snow toward a \(200-\mathrm{kg}\) boulder but jump off the sled (inertia \(5.0 \mathrm{~kg}\) ) the instant before it hits the boulder. The boulder is sitting on very slick ice and moves freely when the sled hits it. The sled bounces back, moving at \(6.0 \mathrm{~m} / \mathrm{s}\).
(a) At what speed does the boulder move after the sled hits it?
(b) If you stayed on the sled, what would your momentum be just before you hit the boulder?
(c) Suppose you and the sled hit the boulder and continue forward after the collision at \(2.0 \mathrm{~m} / \mathrm{s}\). Would the boulder's after-collision speed be higher or lower than the speed you calculated in part \(a\) ?
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