When a dielectric slab completely fills the space between the plates of a parallel-plate capacitor, the magnitude
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When a dielectric slab completely fills the space between the plates of a parallel-plate capacitor, the magnitude of the bound charge is one-fourth the magnitude of the free charge.
(a) What is the dielectric constant of the material of which the slab is made?
\((b)\) If the slab does not fill the space between the plates, but instead has a width equal to half the distance between the plates, does the magnitude of the bound charge change? If so, how?
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a Lets assume the magnitude of the free charge on the plates of the parallelplate capacitor is Q According to the given information the magnitude of t...View the full answer
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