2.25 moles of an ideal gas with C V ,m = 5/2 R is transformed from an...
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2.25 moles of an ideal gas with CV ,m = 5/2 R is transformed from an initial state T 680. K and P = 1.15 bar to a final state T = 298.K and P = 4.75 bar. Calculate ΔU, ΔH, and ΔS for this process.
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5x8314 Jmol K 2 7x8314J molK AU nCvm AT 225 mol AH n...View the full answer
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