Determine the equilibrium constant for the dissociation of sodium at 298 K: Na 2 (g) 2Na
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Determine the equilibrium constant for the dissociation of sodium at 298 K:
Na2 (g) ⇄ 2Na (g)
For Na2, B = 0.155 cm−1, v̅ = 159 cm−1, the dissociation energy is 70.4 kJ/mol, and the ground-state electronic degeneracy for Na is 2.
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K 9 NA Na 9 NA A Na 9Na 9TgE BED V 77 0 6 2 X Na 9T9R9v9E ...View the full answer
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