For a Hermetian operator A, (x) A (x) dx (x) A (x) dx Assume that A f (x) (a ib) f (x), where a and b are constants Show that if A is a Hermetian operator, b 0 so that the eigenvalues of f (x) are real ...

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For a Hermetian operator A, * (x)[A (x)] dx = (x)[A (x)] * dx. Assume

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For a Hermetian operator Aˆ, ∫ψ^*(x)[Aˆψ (x)] dx = ∫ψ (x)[Aˆψ (x)]^*dx. Assume that Aˆ f (x) = (a + ib) f (x), where a and b are constants. Show that if Aˆ is a Hermetian operator, b = 0 so that the eigenvalues of f (x) are real.

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Physical Chemistry

ISBN: 978-0321812001

3rd edition

Authors: Thomas Engel, Philip Reid

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Question Posted: May 17, 2018 12:50 AM

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For a Hermetian operator A, * (x)[A (x)] dx = (x)[A (x)] * dx. Assume

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Physical Chemistry

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