The vapor pressure of methanol(l) is 16.94 10 3 Pa at 298.15 K. Use this value
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The vapor pressure of methanol(l) is 16.94 × 103 Pa at 298.15 K. Use this value to calculate ΔGof (CH3OH, g) − ΔGof (CH3OH, l). Compare your result with those in Table 4.1.
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From the tables G o f C 2 H 5 OH g G o f C 2 H 5 OH l 1623 kJ ...View the full answer
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