Question: Two long parallel wires carry currents of 5 A and 10 A in opposite directions as shown in the diagram below. The distance between the

Two long parallel wires carry currents of 5 A and 10 A in opposite directions as shown in the diagram below. The distance between the wires is 5 cm.
a. What is the magnitude of the force per unit length exerted by one wire on the other?
b. What are the directions of the forces on each wire?
c. What is the total force exerted on a 30-cm length of the 10-A wire?
d. From this force, compute the strength of the magnetic field produced by the 5-A wire at the position of the 10-A wire (F = IlB).
e. What is the direction of the magnetic field produced by the 5-A wire at the position of the 10-A wire?

I= 10 A I = 5 A 5 cm SP1 Diagram

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The magnitude force experienced by each wire is given by the following formula FL 0I 1 I 2 2r 1 The ... View full answer

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